審査済み
2 より大きいすべての偶数は、2つの素数の和で表せるか?(ゴールドバッハ予想)
Is every even integer greater than 2 the sum of two primes?
mathematicsnumber-theoryadditive-number-theory
問題文
Determine whether every even integer n > 2 can be written as n = p + q with p and q prime.
背景
The ternary (odd) version is recorded as solved in formal-conjectures (Helfgott).
アプローチ · 5 件
解決したかどうかは、問いではなくアプローチごとに決まります。Atlas は判定しません。外部の判定者が何をしたかを記録します。
Lean 4 formalization (formal-conjectures)
形式証明
- 到達状況
- 未着手
- 判定者
- the Lean 4 typechecker, against the pinned toolchain · 型検査
- 定式化
- Every even integer greater than 2 is the sum of two primes, stated in Lean 4.問いと同値Lean v4.33.1 + mathlib@0df444a3 (formal-conjectures@fc2696b2)検証対象を見る
保たれているもの
- The universal quantifier over even integers
- Exactly two prime summands
加えられた仮定・条件
- The bound 'greater than 2' made explicit
Statement only; no proof exists in the repository.
The circle method
査読付きの証明
- 到達状況
- 進行中
- 判定者
- the analytic number theory community, through journal peer review · 査読
- 定式化
- Estimate the number of representations of an even N as p + q by major and minor arc analysis of exponential sums over primes.問いと同値
保たれているもの
- The exact representation count, if the error term can be controlled
弱まっているもの
- For two primes the minor-arc error is not smaller than the main term, so the method yields 'almost all even numbers' rather than 'all'
加えられた仮定・条件
- Nothing arithmetic; the cost is analytic control that is currently unavailable
The same method settles the ternary problem: Vinogradov (1937) for large odd N, Helfgott (2013) for every odd N > 7.
閉じた道
- The circle method controls the binary problem only up to an exceptional set: Montgomery-Vaughan (1975) give density zero, not emptiness. Closing that gap is the whole difficulty, not a technical remainder.無条件
- paperdoi:10.4064/aa-27-1-353-370H. L. Montgomery, R. C. Vaughan, The exceptional set in Goldbach's problem, Acta Arith. 27 (1975) 353-370
証拠
- preprintarXiv:1312.7748H. A. Helfgott, The ternary Goldbach conjecture is true (2013); accepted for Annals of Mathematics Studies after referee revisions
- paperdoi:10.4064/aa-27-1-353-370H. L. Montgomery, R. C. Vaughan, The exceptional set in Goldbach's problem, Acta Arith. 27 (1975) 353-370
- paperI. M. Vinogradov, Representation of an odd number as a sum of three primes, Dokl. Akad. Nauk SSSR 15 (1937) 291-294The ternary problem for sufficiently large odd numbers, by the circle method
Sieve methods
査読付きの証明
- 到達状況
- 進行中
- 判定者
- the analytic number theory community, through journal peer review · 査読
- 定式化
- Bound below the number of representations N = p + q by sieving the shifted primes, as in Chen's theorem.問いより弱い
保たれているもの
- A representation of every large even number as a prime plus something with few prime factors
弱まっているもの
- Chen's theorem allows the second summand to be a product of two primes; it is not the conjecture
加えられた仮定・条件
- Sieve dimensions and level-of-distribution hypotheses
閉じた道
- A sieve alone cannot detect primes (Selberg's parity problem): it cannot separate 'p + prime' from 'p + product of two primes', which is exactly the gap Chen's theorem leaves.無条件
- talkA. Selberg, On elementary methods in prime number theory and their limitations, Den 11te Skandinaviske Matematikerkongress, Trondheim (1949), 13-22The parity obstruction: a sieve cannot distinguish an odd from an even number of prime factors
証拠
- paperJ. R. Chen, On the representation of a larger even integer as the sum of a prime and the product of at most two primes, Sci. Sinica 16 (1973) 157-176Every sufficiently large even number is p + q with q prime or a product of two primes
Exhaustive computation
計算による判定
- 到達状況
- 進行中
- 判定者
- execution against published tables, reproducible by rerunning the search · 実行
- 定式化
- Verify every even integer as a sum of two primes for every case up to a finite bound.問いより弱い
保たれているもの
- The exact arithmetic claim, case by case
弱まっているもの
- Only finitely many cases; the question is about all of them
加えられた仮定・条件
- Trust in the search code and in the prime tables it consumes
閉じた道
- A finite search cannot settle a statement quantified over all integers; it can only refute it by finding a counterexample.無条件
- paperdoi:10.1090/S0025-5718-2013-02787-1T. Oliveira e Silva, S. Herzog, S. Pardi, Empirical verification of the even Goldbach conjecture and computation of prime gaps up to 4x10^18, Math. Comp. 83 (2014) 2033-2060
Cramer-style probabilistic model
専門家の合意
- 到達状況
- 判定者なし・判定がつかない
- 判定者
- none: a heuristic model has no decision procedure · 判定手続きなし
- 定式化
- Model the primes as independent random events with density 1/log n and read off a representation of every even number as a sum of two primes as an overwhelmingly likely consequence.問いとずれている
保たれているもの
- Predicts the same answer as the conjecture, and matches the computed data
弱まっているもの
- Predicts, never proves: a probabilistic model cannot settle an arithmetic statement
加えられた仮定・条件
- Independence between prime events, which is false in detail
閉じた道
- Maier's theorem shows the Cramer model gives the wrong prediction for primes in intervals of length (log x)^lambda, so its predictions in short intervals cannot be trusted as evidence.無条件
- paperdoi:10.1307/mmj/1029003189H. Maier, Primes in short intervals, Michigan Math. J. 32 (1985) 221-225: the Cramer model predicts the wrong count in intervals of length (log x)^lambda
つながり
関連する問い
- p と p+2 がともに素数となる組は無限にあるか?(双子素数予想)
根拠: Both are Landau problems attacked with sieve methods; Chen's theorem is the strongest classical partial result toward each.
出典
- repositoryhttps://github.com/google-deepmind/formal-conjectures@fc2696b2f863e642ef1452938b0f031f5af5bed3FormalConjectures/Wikipedia/GoldbachConjecture.lean:33
- otherC. Goldbach, letter to L. Euler, 7 June 1742 (letter XLIII of the Euler-Goldbach correspondence)The original conjecture; Euler's reply of 30 June 1742 states the two-prime form used today
- talkE. Landau, Geloeste und ungeloeste Probleme aus der Theorie der Primzahlverteilung und der Riemannschen Zetafunktion, Proc. 5th International Congress of Mathematicians, Cambridge (1913) 93-108The 1912 ICM address listing the four problems, including this one
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